610(t)=16t^2

Solution for 610(t)=16t^2 equation:

610(t)=16t^2

We move all terms to the left:

610(t)-(16t^2)=0

determiningTheFunctionDomain
-16t^2+610t=0

a = -16; b = 610; c = 0;
Δ = b2-4ac
Δ = 6102-4·(-16)·0
Δ = 372100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{372100}=610$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(610)-610}{2*-16}=\frac{-1220}{-32}
=38+1/8
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(610)+610}{2*-16}=\frac{0}{-32}
=0
$